Re: [discussion_vu] VU 2nd Convocation

Asalam o Alaikum miss,
inshallah i will send u all mid terms material and quize . plz frst promise to  not share it to any other. if u agree then reply me on that id  mc080402871@vu.edu.pk  or sms on 03462179699. then i will send u soon.  inshallah that material will help u in mid terms exam.
FIN630 (Investment analysis)
FIN622 ( Corporate Finance)
FIN621 (Financial statement analysis)
MGT603 (Strategic Management)
FIN623 ( Taxation management)
MGT 201(Financial Management)
 
 
Muhammad Nadeem Khan
mc080402871
MBA(finance)
03462179699
best of luck and ALLAH hafiz

 

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Re: [discussion_vu] VU 2nd Convocation

ap ne kab clear ki study aur kitni dair k baad ap ko convocation kaliye bulayaa

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Re: [discussion_vu] fin 619 presentation

yar MBA waly theek reh gy ho foran he result a gea ha ap logon ka........Mera MIT ka project viva 10th march ko hoa tha but still waiting for result :( don't know how log we have to wait more :(/ ...........

On Tue, Apr 19, 2011 at 7:23 AM, mc080403140 Tahira Sarwar <mc080403140@vu.edu.pk> wrote:

Salam Friends,

 

My Presentation was Held near Lawrance Garden, My Presentation was cleared and Ultimatly MBA Finance.

 

Good Luck for you All

 

 

Naveed Aslam Mughal

Distribution Incharge

Organique Whole Foods

 

 

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Re: [discussion_vu] fin 619 presentation

Salam Friends,

 

My Presentation was Held near Lawrance Garden, My Presentation was cleared and Ultimatly MBA Finance.

 

Good Luck for you All

 

 

Naveed Aslam Mughal

Distribution Incharge

Organique Whole Foods

 

 

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[discussion_vu] CS401_Q01_Clarification_with_Reference

---------- Forwarded message ----------
From: ..::ISHFAQ::.. <mc100402092@vu.edu.pk>
Date: Tue, Apr 19, 2011 at 2:32 AM
Subject: CS401_Q01_Clarification_with_Reference
To: zavia-lms <zavia-lms@googlegroups.com>, afaaq <afaaqtariq233@gmail.com>, Miss Kazmi <mc100402020@vu.edu.pk>, coool_vu_students <coool_vu_students@googlegroups.com>

اسلام علیکم ورحمتہ اللہ و برکاتہ

Dear All, i have found another solution of CS401 , Question n o 1 which totally wrong.

Question No. 1

a)       Suppose your computer has a processor with 24-bit address lines. What is maximum amount of memory that can be attached in your system? (Show the step(s) for calculation of maximum addressable memory) (2.5 marks)

2^24 = 16777216
16777216/8 = 2097152bytes
2097152/1024=2048KB
2048/1024 = 2MB

 b)       How many address bits are required for accessing 1GB RAM? (Show the step(s)for calculation of required address bits) (2.5 marks)

1GB*1024=1024MB
1024MB*1024=1048576KB
1048576KB*1024=1073741824bytes
1073741824Bytes*8=8589934592bits
2^33 = therefore 33 address lines exist
Correct is this Method:See the attachment for reference

However the maximum memory iAPX88 can access is 1MB which can be

accessed with 20 bits.

 

2^20=1048576 bytes

=1024 KB

=1 MB

See the attachment for Refrence which is taken from the handout at page number 12.Correct Solution are given Below.
2^24 = 16777216 Bytes
=16384KB
=16MB
Also
1GB*1024=1024MB
1024MB*1024=1048576KB
1048576KB*1024=1073741824bytes
2^30 = 1073741824bytestherefore 30 address lines exist

Best Wishes,

"...SUBHANALLAHI WABI HAMDIHI...SUBHANALLAH IL AZEEM..."
Muhammd Ishfaq
MCS 2nd Semester (PakPattan)

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MBA 4^th (Final Semester) Finance Group
Afaaq_Tariq@yahoo.com
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